Peter and Paul are two friends The sum of their ages is 35 years Peter is twice as old as

Supposing Peter’s age is X and Paul’s age is Y
We have X + Y = 35.. (1)
Now when Peter was Paul’s age which means (X - Y) years ago
Peter would have been X - (X - Y) = Y which is Paul’s age now
Paul would have been Y - (X - Y) = 2Y - X
We have been given that Peter’s age is twice what Pauls was,
so X = 2(2Y - X) = 4Y - 2X which gives 3X = 4Y………………….. (2)

For ease of use if X + Y = 35; then 3X + 3Y = 105.
I.E. 4Y + 3Y =105 from (2) above
7Y = 105

Y= 15; X = 20
12 years agoHelpfull: Yes(6) No(3)
let peter&paul present ages be x&y respetively

so x+y=35

from question it is clear that peter is older

so let us assume m years back peter
y=2(y-m)
so y=2m
and
y=x-m

x-m=2m
x=3m

from x+y=35
m=7

hence x=21 and y=14
12 years agoHelpfull: Yes(4) No(2)
Peter is 21 yrs old currently....When paul was 7 yrs old at that time Peter would be 14 yrs old as per the question...and now peter is 21 yrs old and Paul is 14.
12 years agoHelpfull: Yes(3) No(4)
For example x,y ages are 20 and 15 if x is in y's age it means 15 10 so answer is 15
12 years agoHelpfull: Yes(1) No(5)

Peter and Paul are two friends. The sum of their ages is 35 years. Peter is twice as old as Paul was when peter was as old as Paul is now. What is the present age of peter??
Plz give the explanation.