IBM
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Numerical Ability
Area and Volume
SURFACE AT RS20 PER SQ.METER, IF THE HEIGHT OF THE CHIMNEY IS 56M A THERMAL CHIMNEY OF CIRCULAR CROSS SECTION HAS OUTER AND INNER RADII OF 3M AND 2M RESPECTIVELY. FIND THE COST OF CEMENT FINISHING FOR THE INNER AND OUTER.
Read Solution (Total 3)
-
- 2*pi*h*(R+r)
=2*22/7*56*(3+2)
=44*8*5
35200 - 9 years agoHelpfull: Yes(20) No(2)
- Perimeter=2*pi*h*(R+r)
= 2*22/7*56*5
=17600
cost of cement= 20*17600
=352000rs
- 9 years agoHelpfull: Yes(9) No(0)
- 17600 Rs.
If height=h, R=Outer radius & r=inner radius, then
Total Surface Area= Outer surface area+ Inner surface area=(2*Pi*R*h)+ (2*Pi*r*h)=2*Pi*h(R+r)
=2*(22/7)*56*[(3/2)+(2/2)]= 880 m^2
So cost of cement finishing @ 20Rs./m^2= 20*880=17600 Rs. - 10 years agoHelpfull: Yes(5) No(12)
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