From 3 men and 4 women, three persons are to be selected in such a way that at least one women is selected. In how many different ways can they be selected?
a) 60
b) 42
c) 21
d) 36
e) None of these

• e) None of these
  
  All 3 women = 4 ways ( leaving one woman each time )
  2woman +1 man = 4C2 *3 = 6*3= 18
  1 woman +2 men = 4*3C2 = 4*3= 12
  
  total ways = 4+18+12= 34 ways
  
  so none of these.
• 12 years agoHelpfull: Yes(3) No(2)
• this is the question of probability that is combination
  for selecting there are following case of choosing the team
  2men1women=3c2*4c1=12
  1men2women=3c1*4c2=18
  0men3women=3c0*4c3=4
  there total ways r 12+18+4=34ways
• 12 years agoHelpfull: Yes(3) No(2)
• 2M1W=12(3c2*4c1)
  1M2W=18(3c1*4c2)
  0M3W=4(3c0*4c3)
  total=34 ways
• 12 years agoHelpfull: Yes(0) No(2)