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Maths Puzzle
Numerical Ability
Boats and Streams
The sum of the present ages of A, B, C is 45 yrs. Three years ago their ages were in the ratio 1:2:3. What
is the present age of A
a) 10yrs b) 6yrs c) 8yrs d) 9yrs
Read Solution (Total 4)
-
- a:b:c=1:2:3
a=1x;b=2x;c=3x;
after three years
(x+3)+(2x+3)+(3x+3)=45;
x=6;
so present age of a will be x+3=6+3=9;
so ans is d; - 12 years agoHelpfull: Yes(10) No(1)
- The sum of the present ages of A, B, C is 45 yrs. Three years ago, sum of their ages was 45 -3*3= 36 yrs
Three years ago their ages were in the ratio 1:2:3.
so three yrs ago, age of A was 26*1/6= 6 yrs
Present age of A = 6+3=9 yrs - 12 years agoHelpfull: Yes(8) No(2)
- age of a=9 as k+2k+3K+9=45
- 12 years agoHelpfull: Yes(4) No(0)
- Given sum (A+B+C)=45
Ratio 3 years ago 1:2:3
Present age = 1x + 2x + 3x +9 =45(Since 3 years ago ratio 3+3+3=9)
6x+9=45; x=6
Present age of A=x+3 ;6+3=9 so option d)9yrs - 7 years agoHelpfull: Yes(1) No(0)
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