If 3 houses are to be painted, Mr. A can paint a house in 6 days(nos are not same)...Mr. B can do the same in 8 days...& Mr. in 12 days. if Mr. A does the work for 8 days & leaves for vacation, & Mr. B continues the work for the next 6 days, for how many days should Mr. work?

• 8/6 + 6/8 + x/12 =3
  
  ===>11!!!!
• 12 years agoHelpfull: Yes(67) No(5)
• Mr.C work for 11days to complete the work.
  
  3 houses to be paint.
  Mr.A can paint 1 house in 6 days.
  Mr.B can paint 1 house in 8 days.
  Mr.C can paint 1 house in 12 days.
  
  If Mr.A paints for 8 days, he paints = 8/6 houses
  If Mr.B paints for 6 days, he paints = 6/8 houses
  
  So, remaining painting work have to be done by Mr.C is,
  
  Days to work for Mr.C = 3 - 8/6 + 6/8
  
  = 3 - 32/24 + 18/24
  = 3 - 50/24
  =(3/1)-(50/24)
  = 72/24 - 50/24
  = 22/24
  = 11/12.
  
  So, Mr.C working for 11days to complete the remaining painting for house.
• 12 years agoHelpfull: Yes(60) No(4)
• Mr.A = 1/6 paint/days
  Mr.B = 1/8 paint/days
  Mr.C = 1/12 paint/days
  
  3 house to be painted
  
  Mr.A = 1/(6*3) paint/days for 3 house
  Mr.B = 1/(8*3) "
  Mr.C = 1/(12*3) "
  
  Equation becomes ->
  
  [(1/(6*3))*8] + [(1/(8*3))*6] + [(1/(12*3)*x)] = 1
  
  //(Work/days)*days done = 1
  
  Solving eqn, x = 4
  
  So Mr.C needs to work for 4 days
• 12 years agoHelpfull: Yes(1) No(17)
• ans=14
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• 11 years agoHelpfull: Yes(1) No(10)
• 25 days............
• 12 years agoHelpfull: Yes(0) No(47)