In a right angled triangle ABC angle B = 90 , BM is the median to AC , then AB^2 + BC^2 (in terms of BM)

• 
  
  Given B=90 & BM is median to AC
  Thus AM=MC,
  AC=2BM
  Pythogarus Theorem,
  AB2+BC2 = AC2
  Now,
  AC = 2*BM
  So, AB2+BC2 = (2*BM)2 = 4BM2
• 11 years agoHelpfull: Yes(49) No(9)
• at vertex b median divides exactly 45 degrees between triangles ABM and BCM
  so AB=SQRT(2)BM BC=SQRT(2)BM
  ab2+bc2=4bm2
• 10 years agoHelpfull: Yes(1) No(0)