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a string of pearls such that 1/3 is lost and of that 1/4th is missing, remaining is 20 then actual number of pearls?
Read Solution (Total 12)
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- let the no of pearls be=x
then 1/3 get lost so remaining =x-x/3=(2x/3)
and from that 1/4 is missing so=(2x/3)-(2x/12)=x/2
and remaining is equal to 20
so x/2=20
x=40 i think so.... - 11 years agoHelpfull: Yes(65) No(15)
- 48 is the actual number of pearls.
Let total Number of Pearls = x
Number of pearls lost = x/3
Number of pearls missing = x/4
Remaining Pearls = 20
==> x = x/3 + x/4 + 20
==> x = (4x+3x)/12 + 20
==> x = (7x + 240) / 12
==> 12x = 7x + 240
==> 5x = 240
==> x = 240/5
==> x = 48..
Missing Pearls = x/3 = 48/3 = 16 pearls
Lost pearls = x/4 = 48/4 = 12 pearls
Remaining = 20
So, total = 16+12+20 = 48pearls. - 13 years agoHelpfull: Yes(49) No(29)
- let no.of pears be X;
1/3 is lost, i.e 1/3of X
Remaining= X-(1/3)x
= (2/3)x
Now missing = 1/4th of (2/3)x; i.e 1/4 *(2/3)x = (2/12)x =(1/6)x
Final remaining pears = (2/3)x- (1/6)x = (3/6)x = (1/2)x
given remaining pears is 20;
there4 , (1/2)x=20
=> x = 20*2
=> x=40. ans - 11 years agoHelpfull: Yes(11) No(1)
- 1/3 x + 1/4 x= 7/12 x
(1 - 7/12) x =20
=> 5/12 x = 20 => x =48 - 11 years agoHelpfull: Yes(6) No(11)
- Answer will be 40
- 11 years agoHelpfull: Yes(6) No(2)
- x-(x/3+x/4)=20
5x/12=20
x=48 - 11 years agoHelpfull: Yes(5) No(6)
- lets in beginning der is 100% pearl
den 1/3 of dem lost=33%
100-33=66% approx
den 25% of 66=16
66-16=50
this 50%=20 pearl
so 100%=40 pearl - 11 years agoHelpfull: Yes(3) No(1)
- 2*x/3 *3/4=20
=> x/2=20
=>x=40 - 10 years agoHelpfull: Yes(2) No(1)
- X/3+x/4+20=x
on solving we get=48 - 11 years agoHelpfull: Yes(0) No(8)
- let actual no of pearls=x
now from question
(x-x*(1/3))*1/4=20
x*2/3*(1/4)=20
x*1/6=20
x=120 - 11 years agoHelpfull: Yes(0) No(3)
- 1/3 x + 1/4 x= 7/12 x
(1 - 7/12) x =20
=> 5/12 x = 20
Final ANS --->48 - 10 years agoHelpfull: Yes(0) No(5)
- ans is 48
now to prove that
1/3 of 48+1/4 of 48+20=48 - 9 years agoHelpfull: Yes(0) No(0)
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