Find the equation whose roots are 9 and 5?

• Answer is x^2 - 14x + 45 = 0.
  
  Given that, roots of the equation are 9 and 5
  
  Therefore, the required quadratic equation is
  x^2 - (a + b)x + (a*b) = 0.
  
  Substituting the value of roots in the above equation we get the required equation.
  x^2 - (9+5)x + 9*5 = 0
  x^2 - 14x + 45 = 0.
• 12 years agoHelpfull: Yes(42) No(3)
• (x-9)*(x-5) =0
  x^2 -14x+45 =0
• 12 years agoHelpfull: Yes(26) No(3)
• (x-9)(x-5)=0
  x^2-14x+45=0
• 9 years agoHelpfull: Yes(2) No(1)
• x^2-14x+45=0
  when solve the problem.
  x^2-9x-5x+45=0
  x(x-9)-5(x-9)
  (x-9) (x-5)
  x=9,5
  
• 9 years agoHelpfull: Yes(1) No(0)
• (x-9)(x-5)=0
  
  x^2 -14x +45 =0
• 8 years agoHelpfull: Yes(1) No(0)
• x^2-14x+45
  
• 11 years agoHelpfull: Yes(0) No(1)
• (x-9)*(x-5)=x2-14x+45
• 7 years agoHelpfull: Yes(0) No(0)