Capgemini
Company
Numerical Ability
Permutation and Combination
How many 5 digit no. can b formed wit digits 1, 2, 3, 4, 5, 6 which r divisible by 4 and digits not repeated
Read Solution (Total 1)
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- for divisible by 4 last 2 digit will divisible by 4 so,a/c to qus. last 2 digit will be 12,16,24,32,36,52,56,64 & remaining 3 digit arranged by 4p3 , so ans. will be 4p3*8=192
- 10 years agoHelpfull: Yes(3) No(2)
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