the difference bw the ages of a and c is half the age of b. the diff bw the ages of a and b is one-sixth of the age of c. if the sum of the ages of b and c is 32, find the age of a

• 22 years
  
  A- C= B/2 ---(i)
  A- B= C/6 ---(ii)
  B+ C=32 ---(iii)
  (i) - (ii), gives 3B- 5C =0 ---(iv)
  From (iii) & (iv), B=20, C=12, So A=22
• 9 years agoHelpfull: Yes(5) No(1)
• a-c=1/6*b
  a-b=1/6*c
  b+c=32
  
  a=22,b=20,c=12
• 9 years agoHelpfull: Yes(1) No(2)
• A= 22
  
  Solving
  a -c =1/2 b .....1st
  a - 1/6 c = b .....2nd
  Negating 1st and 2nd, 5c =3b.
  using c=3/5 b in equation b+c=32 we get c= 12 b=20
  
  
  Putting this value in 1st we get a= 22.
• 9 years agoHelpfull: Yes(1) No(1)