if x-y + z = 19 , y + z =20, x-z=3, find d value of x+4y-5z
22 38 17 none

• If x-y + z = 19 , y + z =20, x-z=3,
  
  solving these, we get
  x=15,y=8, z=12
  
  x+4y -5z= 15+32-60 = -13 .. none of these.
• 12 years agoHelpfull: Yes(22) No(2)
• x-y+z=19---------(1)
  y+z=20
  thus y=20-z---------(2)
  x-z=3
  thus x =3+z---------(3)
  substitute x and y in equation (1)
  you will get,
  (3+z) - (20-z) + z = 19
  3z = 36
  z = 12
  substitute z in (2) and (3)
  thus x = 15
  and y = 8
  substitute value of x,y,z in x+4y-5z
  answer is - 13.... none....
  
• 12 years agoHelpfull: Yes(16) No(1)
• add all three eq u will get 2x+z=42
  then find x=15
  then find z=12
  thn find y=8
  so x+4y-5z=15+4*8-5*12
  15+32-60
  47-60=-13
• 9 years agoHelpfull: Yes(0) No(0)
• on simplification of equations we got x=15,y=8,z=15
  on submitting value is=-13
  so ans is none of these.
• 7 years agoHelpfull: Yes(0) No(0)