There r three coins of Re 1, 50 ps, 25 ps having ratio of 13:11:3. the total sum of money is 77, then find out hw mny re. 1 coins is there?

• There r three coins of Re 1, 50 ps, 25 ps having ratio of 13:11:3.
  if There r three coins of Re 1, 50 ps, 25 ps . No of coins are 13x,11x and 3x respectively..
  Then 13x + 11x/2 + 3x/4 =77
  x = 77*8/ (104+44+6) = 77*8/154 = 4.
  
  so no of 1 rupee coins = 13x = 13*4= 52 coins.
• 12 years agoHelpfull: Yes(112) No(9)
• @pargatpal g if we put 4 in eq 13x=52 11x/2=22 and 3x/4=4 but total is not 77 rs ????
• 12 years agoHelpfull: Yes(7) No(60)
• Total sum of money is Rs 77
  So this sum of Rs 77 consists of Re 1, 50 ps , 25 ps
  1Re 50 ps 25 ps
  Now consider the ratio 13 : 11 : 13
  1Re= 100 ps
  ? = 25 ps
  25* 1=100*?
  therefore ?=(1/4)
  Similarily 50 ps= (1/2)
  Now 13: (11/2): (3/4)
  lcm(1,2,4)=4
  So ratio 52 ; 22: 3
  1Re coin (52/77)*77=52 coins
  If 50 ps coins then (22/77)*77=22*2=44 coins (Since two 50 ps make 1Re coin)
  Similarily 25 ps coins then(3/77)*77=3 *4=12 coins (Sice four 25 ps make 1Re coin)
  
• 8 years agoHelpfull: Yes(4) No(0)
• 13x + 11x/2 + 3x/4 =77
  
  x = 77*8/ (104+44+6)
  = 77*8/154 = 4.
  
  Therefore the total no of 1 rupee coins = 13x = 13*4= 52 coins.
• 8 years agoHelpfull: Yes(2) No(0)
• let 1Re coins=13x
  50ps coins=11x
  25ps coin=3x
  total number of coin=13x+.5(11x)+.25(3x)=77
  x=4
  13x=13*4
  =54 ans
  
• 8 years agoHelpfull: Yes(1) No(7)