A person starts walking at a speed of 5km/hr through half the distance, rest of the distance he
covers with aspeed 4km/hr. Total time of travel is 9 hours. What is the maximum distance he
can cover?

• Ans:40..
  t=d/s, so
  9=x/2*1/5+x/2*1/4(because half distance with 5 km/ph, and remaining half with 4km/hr)
  9=x(18/80)
  x=40km
• 11 years agoHelpfull: Yes(8) No(0)
• 40
  
  d[1/10+1/8]=9
  d=40km
• 12 years agoHelpfull: Yes(4) No(3)
• Let, the total distance be x.
  0.5x/5 +0.5x/4 = 9
  x=40
• 8 years agoHelpfull: Yes(2) No(0)