Hexaware
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Numerical Ability
Time Distance and Speed
A person starts walking at a speed of 5km/hr through half the distance, rest of the distance he
covers with aspeed 4km/hr. Total time of travel is 9 hours. What is the maximum distance he
can cover?
Read Solution (Total 3)
-
- Ans:40..
t=d/s, so
9=x/2*1/5+x/2*1/4(because half distance with 5 km/ph, and remaining half with 4km/hr)
9=x(18/80)
x=40km - 11 years agoHelpfull: Yes(8) No(0)
- 40
d[1/10+1/8]=9
d=40km - 12 years agoHelpfull: Yes(4) No(3)
- Let, the total distance be x.
0.5x/5 +0.5x/4 = 9
x=40 - 9 years agoHelpfull: Yes(2) No(0)
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