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Numerical Ability
Age Problem
the age difference between two brothers is 3 years. After 6 years the ratio between the age is 9:8
What are their ages?
Read Solution (Total 11)
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- 21 and 18
x-y=3
x+6/y+6=9/8
solving this we get y=18 and x=21 - 12 years agoHelpfull: Yes(15) No(6)
- Let a = the age of the younger brother now
a+3 = the age of the older brother now
given:
In 6 years:
a+6 = the age of the younger brother
a+3+6 = the age of the older brother
a+9/a+6=9/6
8(a+9)=9(a+6)
8a+72=9a+54
a=18
a+3=21 - 10 years agoHelpfull: Yes(6) No(2)
- x-y=3
x+6/y+6=9/8
x=18
y=21 - 10 years agoHelpfull: Yes(3) No(4)
- no matter what the age of the brothers the ratio will remain the same
elder bro age=x
younger bro age=x-3
ratio=9/8
x/x-3=9/8
solving we get x=27
x-3=24
- 10 years agoHelpfull: Yes(2) No(5)
- x+3+6/x+6=9/8
So x=18
and x+3=21 - 10 years agoHelpfull: Yes(1) No(3)
- let the age of ist brother =x therefore age of 2nd brother =x-3 after 6 yr age of 1st x+6......(1)
age of 2nd x-3+6=x+3......(2)
dividing 1/2 we have x+6/x+3=9/8
after solving we get x=21 and x-3 i.e 21-3=18 yr
- 9 years agoHelpfull: Yes(1) No(1)
- (x+9):(x+6)=9/8 9x+54=8x+72 x= 18, 21
- 8 years agoHelpfull: Yes(0) No(1)
- (x+3)/x=9/8. ==> x=24, x+3=27 ages are 27,24
- 7 years agoHelpfull: Yes(0) No(0)
- let age of younger one is x, and older one is x+3
after 6 years
younger=x+6 and older=x+3+6=x+9
so,
x+9/x+6=9/8
8(x+9)=9(x+6)
8x+72=9x+54
x=18
x+3=18+3=21
ans is 18 and 21 - 6 years agoHelpfull: Yes(0) No(0)
- let the age of ist brother =x therefore age of 2nd brother =x-3 after 6 yr age of 1st x+6......(1)
age of 2nd x-3+6=x+3......(2)
dividing 1/2 we have x+6/x+3=9/8
after solving we get x=21 and x-3 i.e 21-3=18 yr. - 6 years agoHelpfull: Yes(0) No(0)
- 58 and 61
- 6 years agoHelpfull: Yes(0) No(2)
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