the age difference between two brothers is 3 years. After 6 years the ratio between the age is 9:8
What are their ages?

• 21 and 18
  x-y=3
  x+6/y+6=9/8
  solving this we get y=18 and x=21
• 12 years agoHelpfull: Yes(15) No(6)
• Let a = the age of the younger brother now
  a+3 = the age of the older brother now
  given:
  In 6 years:
  a+6 = the age of the younger brother
  a+3+6 = the age of the older brother
  
  a+9/a+6=9/6
  
  8(a+9)=9(a+6)
  8a+72=9a+54
  
  a=18
  a+3=21
• 10 years agoHelpfull: Yes(6) No(2)
• x-y=3
  x+6/y+6=9/8
  x=18
  y=21
• 10 years agoHelpfull: Yes(3) No(4)
• no matter what the age of the brothers the ratio will remain the same
  elder bro age=x
  younger bro age=x-3
  ratio=9/8
  x/x-3=9/8
  solving we get x=27
  x-3=24
  
  
• 10 years agoHelpfull: Yes(2) No(5)
• x+3+6/x+6=9/8
  So x=18
  and x+3=21
• 10 years agoHelpfull: Yes(1) No(3)
• let the age of ist brother =x therefore age of 2nd brother =x-3 after 6 yr age of 1st x+6......(1)
  age of 2nd x-3+6=x+3......(2)
  dividing 1/2 we have x+6/x+3=9/8
  after solving we get x=21 and x-3 i.e 21-3=18 yr
  
• 8 years agoHelpfull: Yes(1) No(1)
• (x+9):(x+6)=9/8 9x+54=8x+72 x= 18, 21
• 8 years agoHelpfull: Yes(0) No(1)
• (x+3)/x=9/8. ==> x=24, x+3=27 ages are 27,24
• 7 years agoHelpfull: Yes(0) No(0)
• let age of younger one is x, and older one is x+3
  after 6 years
  younger=x+6 and older=x+3+6=x+9
  so,
  x+9/x+6=9/8
  8(x+9)=9(x+6)
  8x+72=9x+54
  x=18
  x+3=18+3=21
  ans is 18 and 21
• 6 years agoHelpfull: Yes(0) No(0)
• let the age of ist brother =x therefore age of 2nd brother =x-3 after 6 yr age of 1st x+6......(1)
  age of 2nd x-3+6=x+3......(2)
  dividing 1/2 we have x+6/x+3=9/8
  after solving we get x=21 and x-3 i.e 21-3=18 yr.
• 6 years agoHelpfull: Yes(0) No(0)
• 58 and 61
• 6 years agoHelpfull: Yes(0) No(2)