F(x): sq root of x ,g(x) : cube root of x, then find value: f(f(x)+g(x))

• f(x) = x^(1/2)
  g(x) = x^(1/3)
  f(f(x)+g(x))= [ x^(1/2) + x^(1/3) ] ^ (1/2)
  [ x^((1/2)*(1/3))]^ (1/2)
  [ x^ (1/6) ]^(1/2)
  = x^(1/12)
• 9 years agoHelpfull: Yes(5) No(2)
• f(x)= x2
  g(x)=x3
  f(f(x)+g(x))= f(x2+x3)=(x2+x3)^2 = x^4+2*x^5+x^6
• 12 years agoHelpfull: Yes(0) No(11)