In an interview , the probability of appointing Husband is 1/5 while that of wife is
¼.find probability that only one of them get selected in interview.

• 7/20
  p(H)=1/5
  p(w)=1/4
  P(H bar)=1-1/5=4/5
  p(w bar)=1-1/4=3/4
  Required probability=p(H)*p(w bar)+p(w)*p(H bar)
  1/5*3/4+1/4*4/5
  7/20
  
  
• 13 years agoHelpfull: Yes(44) No(4)
• p(H)=1/5
  p(w)=1/4
  p( H bar)=1-1/5=4/5
  p(w bar)=1-1/4=3/4
  not selecting both of them=4/5*3/4=3/5
  selecting one of them= 1-3/5=2/5
  2/5
• 10 years agoHelpfull: Yes(0) No(9)