If A(2,3) ,B(-2,-3) and C(1,2) are three vertices of a triangle ,which
among the following is the largest angle ?

1. ABC 2. BCA 3. CAB 4. All three angles
are equal

• Using distance formula,
  we get AB=sqrt(52), AC=sqrt(2), BC=sqrt(34) where sqrt(x) is square root of x
  As AB is largest side, it's opposite angle which is BCA should be largest.
  
  Second method is to roughly plot the points on coordinate axis and you'll get instantly that BCA is largest angle simply by looking at it.
• 12 years agoHelpfull: Yes(18) No(3)
• roughly plot it and just get the answer. it is BCA clearly
• 11 years agoHelpfull: Yes(14) No(2)
• simply can we done b roughly plotting it
• 11 years agoHelpfull: Yes(3) No(1)
• Finding the all sides using distance formula we will find that BC is the longest side.
  
  the angle opposite to greatest side is greatest.
  
  hence angle A will be greatest.(angle is always measured in anticlockwise direction)
  
  hence ans will be angle CAB.
• 10 years agoHelpfull: Yes(1) No(4)
• 3. CAB (ans)
• 11 years agoHelpfull: Yes(0) No(10)
• gradient(AB)=(-3-3)/(-2-2)=3/2
  gradient(BC)=5/3
  gradient(CA)=1
  |gradient(AB) - gradient(BC)| = 1/6
  |gradient(AC) - gradient(CA)| = 1.....(LARGEST)
  |gradient(CA) - gradient(AB)| = 1/2
  so
• 9 years agoHelpfull: Yes(0) No(1)
• seems BCA by a rough graph plot by those points
  
• 9 years agoHelpfull: Yes(0) No(0)