The sum of one-half, one-third and one-fourth of a number exceeds the number by 12. The number is
(1)144
(2) 154
(3) 90
(4) 174

• option 1 144
  x/2+x/3+x/4=x+12
  13x/12=x+12
  x=144
• 12 years agoHelpfull: Yes(13) No(0)
• x/2+x/3+x/4=x+12
  x=144
• 12 years agoHelpfull: Yes(2) No(1)
• let number is x then according to question we have x/3+x/2+x/4=x+12 and hence get x=144.
  
• 12 years agoHelpfull: Yes(0) No(0)
• ans:: 144
  
  soln:: let no be x
  => (x/2)+(x/3)+(x/4)-12=x
  => x - [x/2+x/3+x/4] = -12
  =>(24x-26x)/24 = -12
  => (-2x)= -12*24
  => x= 144 (answer)
• 12 years agoHelpfull: Yes(0) No(0)
• x*((1/2)+(1/3)+(1/4))=x+12
  x*(13/12)=x+12
  x=144
• 12 years agoHelpfull: Yes(0) No(0)
• (x/2)+(x/3)+(x/4)=x+12
  13X=12x+144
  x=144
• 12 years agoHelpfull: Yes(0) No(0)
• Lcm of 2,3,4 is 12.12*12=144
  
• 12 years agoHelpfull: Yes(0) No(0)
• let number is x.
  from given question ,
  x/2+x/3+x/4=x+12
  13x/12=x+12
  x/12=12
  x=144
• 8 years agoHelpfull: Yes(0) No(0)
• x/2+x/3+x/4=x+12
  6x+4x+3x= 12(x+12)
  13x = 12x+ 144
  x= 144
  option (1)
• 8 years agoHelpfull: Yes(0) No(0)
• answer is (1) 144
• 7 years agoHelpfull: Yes(0) No(0)
• (1/2+1/3+1/4)x=x+12
  or, x=144
• 5 years agoHelpfull: Yes(0) No(0)