A farmer divides his herd of x cows among his 4 sons so that one son gets one half of the herd, the second gets one-fourth, the third gets one-fifth and the fourth gets 7 cows. Then x is equal to
(1) 100
(2) 140
(3)180
(4) 160

• 140
  
  sol: no. of cows:: x
  1st son: x/2
  2nd son: x/4
  3rd son: x/5
  4th son: 7
  
  (x)+(x/4)+(x/5)+7=x
  => x - (19x/20)=7
  => (20x-19x)/20=7
  => x =140 (answer)
  
• 12 years agoHelpfull: Yes(22) No(4)
• Fourth son gets x-(x/2 +x/4 +x/5)
  Therefore, x - 19x/20=7
  or, x/20=7
  therefore x=7*20=140.
  Hence, the correct option is (2).
• 12 years agoHelpfull: Yes(6) No(2)
• 2)140
  x/4+x/5=7
• 12 years agoHelpfull: Yes(4) No(0)
• Option 2 140
  
  x/2+x/4+x/5+7=x
  19x/20+7=x
  x=140
• 12 years agoHelpfull: Yes(1) No(2)
• (x/2)+(x/4)+(x/5)+7=x
  x=140
• 12 years agoHelpfull: Yes(1) No(0)
• x=x/2+x/4+x/5+7
  from this formula
  20x=19x+140
  x=140
• 12 years agoHelpfull: Yes(1) No(0)
• from the data 7*20=140
• 12 years agoHelpfull: Yes(1) No(0)
• x/2+x/4+x/5+7=x
  38x+280=40x
  2x=280
  x=140
• 8 years agoHelpfull: Yes(0) No(0)
• x/2 + x/4 + x/5 +7 = x
  19x + 140 = 20x
  => x= 140
• 6 years agoHelpfull: Yes(0) No(0)