in a railway station, there are tow trains going. One in the harbour line and one in the main line, each having a frequency of 10 minutes. the main line service starts at 5 o'clock. the harbour line starts at 5.02a.m. a man goes to the station every day to catch the first train. what is the probability of man catchinhg the first train

• Name train of the main line(first train) as train1 and other train as train2.
  Now let the man go to the station at 5:00. He catches train1. Now let the man go to the station at 5:01, he catches train2. If he goes at 5:02, he catches train2 again. If he goes at 5:03 he catches train1(train 1 comes again at 5:10 as the freq is 10 min). At 5:04....5:09 (total 7 min) he still catches train1. At 5:10 the situation repeats as from 5:00 so dont take 5:10 into our prob. So in those 10 min total number of times he got first train i.e train1 is 8 times. So probability of catching first train(train1) is
• 14 years agoHelpfull: Yes(6) No(1)
• The ans did not get printed. Let me finish. Probability of catching first train(train1) is 8/10=4/5
• 14 years agoHelpfull: Yes(4) No(0)