Q. B is 8km East of A. C is 6km North of B. D is 12km East of C. E is 16km North of D. What is the distance b/w A and E.

Option
a) 20km
b) 22km
c) 18km
d) 30km

• it will make two rightangle triangles
  1. 1st triangle ABC AB=8km & BC=6km.So AC=Squareroot(64+36)=10km.
  2. 2nd triangle CDE CD=12km & DE=16km.So CE=Squareroot(144+256)=20km.
  So, AC+CE = AE = 30km.
• 11 years agoHelpfull: Yes(11) No(0)
• root (22^2 + 20^2) = root 884 = 29.73 km
• 12 years agoHelpfull: Yes(2) No(3)
• city B is 8 km east of A,
  city C is 6 km north of B
  city D is 12 km east of C
  city E is 16 km north of D
  If we produce ED and AB then these will meet each other at F say.
  Then AEF is a right angled triangle with sides AF = 20 and EF = 22.
  The hypotenuse AE = ( 20^2 +22^2)^(1/2) = (884)^(1/2) = 29.73
  So Answer is none of these options.
• 12 years agoHelpfull: Yes(1) No(0)