Q. A room is 30 X 12 X 12. a spider is ont the middle of the samller wall, 1 feet from the top, and a fly is ont he middle of the opposite wall 1 feet from the bottom. what is the min distance reqd for the spider to crawl to the fly.

• h=30; b=12; h=12;
  
  ..............
  | " |
  | |
  | | 12
  | |
  | " |
  |..............|
  30
  
  Apply Geometry to get the minimum distance.
  
  Mid-point [A] of side wall is at 6.
  Spider [B] is at 5 from Mid-point of side wall (or) 11 from bottom (or) 1 form top.
  Center point [C] of box is 15 away form the mid-point of side wall.
  
  Then ABC is a right angled triangle.
  Sides AB=5; AC=15;
  Angle at A=90 degrees
  BC=((AB^2)+(AC^2))^1/2
  BC=15.811
  
  Similarly,
  Mid-point[D] of ooposite sidewall is at 6.
  Fly [E] is at 5 from Mid-point of opposite side wall (or) 11 from top (or) 1 form bottom.
  Center point [C] of box is 15 away form the mid-point of opposite side wall.
  
  Then DEC is a right angled triangle.
  Sides DE=5; DC=15;
  Angle at D=90 degrees
  CE=((DE^2)+(DC^2))^1/2
  CE=15.811
  
  Shortest distance from B(Spider) to E(Fly)
  BE = BC + CE
  BE = 31.622
  
• 11 years agoHelpfull: Yes(10) No(2)
• very simple geometry, use pythagores theorem
  distance b/w them=sq root(30^2+10^2) =31.622
• 9 years agoHelpfull: Yes(3) No(3)