Q. 2/3 of crockery (plates) are broken, 1/2 have some other thing (handle) broken, 1/4 are both broken and handle broken. Ultimately only 2 pieces of crockery were without any defect. How many crockery were there in total.

• let x no of crockery
  therefore total no of defects are x-2;
  (((2/3)*x)+((1/2)*x)-((1/4)*x))=(x-2);
  by solving above equation x=24;
• 8 years agoHelpfull: Yes(2) No(0)
• total x
  2/3x broken it means 1/3x not broken
  1/2 of 1/3x are those whose handles broken=1/6x, remaining is(1/3x-1/6x=1/6x)
  1/4 of 1/6x are those that are brokens with handles =1/24x remaining(1/6x-1/24x=1/8x)
  remaining which are non defective is 2=1/8x
  x=16 plates
• 7 years agoHelpfull: Yes(2) No(2)
• let , x no. are total , so 2*x/3 are broken & 1*x/3 are unbroken. therefore 1*x/3 = 2 , x = 6
  
• 9 years agoHelpfull: Yes(0) No(5)