Q. 55*55*55+45*45*45/55*55-55*45+45*45

• 100
  
  55^3+45^3/55^2+45^2-55*45
  a^3+b^3/a^2+B^2-a*b=a+b
  s0 55+45=100
• 12 years agoHelpfull: Yes(6) No(1)
• a^3+b^3=(a+b)(a^2-ab-b^2)
  
  Ans is 55+45=100
• 12 years agoHelpfull: Yes(3) No(0)
• This is in da form of (a^3+b^3)/(a^2-a*b-b^2)
  a^3+b^3=(a+b)(a^2-a*b+b^2)
  so by putting this formula we get (a+b)
  here a=55 & b=45
  (a+b)=(55+45)=100
• 11 years agoHelpfull: Yes(1) No(0)
• If you consider 5 common from both the numerator and divisor, and cancel it out, then the solution will come out as:
  (11^3+9^3)/(11^2+9^2-11*9)
  which is 11+9=20.
  The fraction should be simplified to least value in such cases.
• 9 years agoHelpfull: Yes(1) No(1)
• this is a form of (a^3+b^3)/(a^2-a*b+b^2)=a+b
  here a=55 & b==45
  so the answer is =a+b=55+45=100
  
• 10 years agoHelpfull: Yes(0) No(0)
• a^3+b^3/a^2-ab+b^2=a+b.......using formula (a+b)^2=(a+b)(a^2-ab+b^2)
  = 55+45=100
• 10 years agoHelpfull: Yes(0) No(0)
• Ans=100
  ((55+45)*(55+45)*(55+45)-3(55+45)*55*45)/(55+45)*(55+45)-3*55*45
  
• 10 years agoHelpfull: Yes(0) No(0)
• 100
  a^3+b^3=(a+b)(a^2-ab-b^2)
• 10 years agoHelpfull: Yes(0) No(0)
• I think its 100.
  55+45=100.
• 10 years agoHelpfull: Yes(0) No(0)
• solution is 100
  its like (a+b)^3/(a^2-ab+b^2)
• 9 years agoHelpfull: Yes(0) No(0)