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.x:y=7:11, y:z=1:7.what is the least possible integral values of x given that z is 11x.
Read Solution (Total 2)
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- 7 and 77
x:y:z=7:11:77
max and min values are 77 and 7 - 12 years agoHelpfull: Yes(0) No(2)
- ANS IS
X=3 - 10 years agoHelpfull: Yes(0) No(2)
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