Six years ago I was three times as old as my brother, and now I am twice as old my brother. Find my brother's age.

a) 8 years b) 24 years c) 12 years d) 16 years

• b) 24years
  
  Let brother's age = x
  And my age = 2x
  
  6 years ago:
  Brother age = x-6
  My age = 2x-6
  
  I was 3 time his age then,
  
  2x-6 = 3(x-6)
  2x-6 = 3x-18
  3x-2x = 18-6
  x = 12
  Brother's age = 12years
  My age now = 2x
  = 2(12)
  = 24years
• 12 years agoHelpfull: Yes(2) No(2)
• ANS: C
  
  Asume my brothers age is x and my age is y
  
  Six years ago I was three times as old as my brother
  Means y-6 = 3(x-6)
  y=3x-12 ---1
  
  now I am twice as old my brother
  Mens y = 2x ---- 2
  
  Solving 1 and 2, y becomes 12
• 12 years agoHelpfull: Yes(1) No(1)
• 
  Let brother's age = x
  And my age = 2x
  
  6 years ago:
  Brother age = x-6
  My age = 2x-6
  
  I was 3 time his age then,
  
  2x-6 = 3(x-6)
  2x-6 = 3x-18
  3x-2x = 18-6
  x = 12
  Brother's age = 12years
  My age now = 2x
  = 2(12)
  = 24years
• 10 years agoHelpfull: Yes(0) No(0)