Patni Company Numerical Ability Time Distance and Speed

A train after traveling 50 kms from A meets with an accident and proceeds at 4/5th of the former speed and reaches B, 45 min late. Had the accident happened 20 kms further on, it would have arrived 12 mins sooner. Find the original speed and the distance.

Read Solution (Total 2)

If it means 45-12= 33 mins late than scheduled time, then

speed = 25 kmph and distance = 125 kms.

scheduled time = 5 hrs.
Time taken in first case = 50/25 + 75/20 = 2+3.75 hrs = 5.75 hrs = 5 hrs 45 min

in second case, time taken = 70/25 + 55/20 = 111/20 hrs = 5 hrs 33 mins
13 years agoHelpfull: Yes(1) No(9)

Is the statement correct?

If after accident, the speed is reduced, the train can not reach sooner than scheduled time in second case.

Is 12 minute sooner relative to scheduled time or w.r.t . case 1?
13 years agoHelpfull: Yes(0) No(0)

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