You are given three coins: one has heads on both faces, the second has tails on both faces,
and the third has a head on one face and a tail on the other. You choose a coin at random and
toss it, and it comes up heads. The probability that the other face is tails is
(A) 1/4 (B) 1/3 (C) 1/2 (D) 2/3

• ans = 1/3
  becoz ther is only one chance to get tail on other side of coin,amnog three coins,according to the
  question
• 10 years agoHelpfull: Yes(16) No(7)
• the three coins are HH LL HT
  total possiblity are 6
  1st head probablity are 2/6,
  2 nd head probablity are 0,
  third head probablity are 1/6,
  The total head probablity is 2/6+0+1/6=1/2,
  Then tail probablity is 1-1/2=1/2
• 10 years agoHelpfull: Yes(12) No(10)
• 1st coin probability = 1 (coz both faces have heads)
  2nd coin probability = 1 (coz both faces have tails)
  3rd coin probability = 1/2 (coz heads and tail faces)
  probability = 1 *1*1/2 = 1/2 .
  Ans = c
• 10 years agoHelpfull: Yes(8) No(8)
• h- event of getting head
  n- event of getting normal coin
  p(n|h)= p(n inters. h)/p(h)
  =p(n)*p(h|h)/p(h)
  =(1/3*1/2)/(1/2)
  =1/3
  this is the ans
  
• 10 years agoHelpfull: Yes(6) No(6)
• Bayes Theorem
  P(Heads/3rd coin)=P(getting 3rd coin)*P(getting heads in 3rd coin)/{(P(getting 1st coin)*P(getting heads in 1st coin))+(P(getting 2nd coin)*P(getting heads in 2nd coin))+(P(getting 3rd coin)*P(getting heads in 3rd coin)}
  (1/3*1/2)/{(1/3*1)+(1/3*0)+(1/3)*(1/2)}=1/3
• 8 years agoHelpfull: Yes(3) No(2)
• Answer is 1/2,because we need to get a head that is only possible with 2coins .so1head.1/2
• 9 years agoHelpfull: Yes(1) No(4)
• P(C3/H)= P(C3) P(H/C3) / (P(H) -> 1/3 * 1/2 / (1/3*1+1/3*0+1/3*1/2) ->1/3
• 6 years agoHelpfull: Yes(1) No(1)