The difference between two no is 9 and the product of the two is 14.What is the square of their sum?



a)120 b)130 c)137 d)145

• (c):137
  given: x-y=9,xy=14
  To find: (x+y)^2=x^2+y^2+2xy
  v kw tat (x-y)^2=x^2+y^2-2xy=81
  => x^2+y^2=2xy+81
  =>109.
  Therefore,(x+y)^2=x^2+y^2+2xy== 109+(2*14)==137
  
• 13 years agoHelpfull: Yes(31) No(3)
• Take two numbers as x and y
  The difference between two numbers = x-y = 9
  The product of the two numbers = x*y = 14
  The square of the two numbers sum = (x+y)^2 = (x-y)^2 + (4*x*y) = 9^2 + (4*14) = 81+56 = 137
  Hence, option is 'c'
• 13 years agoHelpfull: Yes(21) No(2)
• let the numbers are x and y.
  so, conditionally, x-y=9,
  xy=14. now, (x+y)2=(x-y)2+4xy
  =9*2+4*14
  =137
• 13 years agoHelpfull: Yes(8) No(2)
• Ans c)137
  use (a+b)^2=(a-b)^2 +4ab
• 13 years agoHelpfull: Yes(7) No(2)
• (x+y)^2=(x-y)^2+4xy
  given x-y=9,xy=14
  so (x+y)2=(9)^2+4*14
  =81+56
  =137
• 10 years agoHelpfull: Yes(0) No(0)
• 137
  (a+b)^2=(a-b)^2+4ab
  9^2+4(14)=137
• 9 years agoHelpfull: Yes(0) No(0)
• 
  (x-y)^2=x^2+y^2-2xy
  here x-y=9 is given
  (9)^2=x^2+y^2-2(14)..........bcz xy=14 is given
  solve this u il get
  x^2+y^2=81+28=109
  
  now by q
  (x+y)^2=x^2+y^2+2xy
  =109+2(14)
  =109+28
  =137
• 9 years agoHelpfull: Yes(0) No(0)