The difference between two no is 9 and the product of the two is 14 What is the square of

Take two numbers as x and y
The difference between two numbers = x-y = 9
The product of the two numbers = x*y = 14
The square of the two numbers sum = (x+y)^2 = (x-y)^2 + (4*x*y) = 9^2 + (4*14) = 81+56 = 137
Hence, option is 'c'
14 years agoHelpfull: Yes(21) No(2)
let the numbers are x and y.
so, conditionally, x-y=9,
xy=14. now, (x+y)2=(x-y)2+4xy
=9*2+4*14
=137
14 years agoHelpfull: Yes(8) No(2)
Ans c)137
use (a+b)^2=(a-b)^2 +4ab
14 years agoHelpfull: Yes(7) No(2)
(x+y)^2=(x-y)^2+4xy
given x-y=9,xy=14
so (x+y)2=(9)^2+4*14
=81+56
=137
11 years agoHelpfull: Yes(0) No(0)
137
(a+b)^2=(a-b)^2+4ab
9^2+4(14)=137
10 years agoHelpfull: Yes(0) No(0)
(x-y)^2=x^2+y^2-2xy
here x-y=9 is given
(9)^2=x^2+y^2-2(14)..........bcz xy=14 is given
solve this u il get
x^2+y^2=81+28=109

now by q
(x+y)^2=x^2+y^2+2xy
=109+2(14)
=109+28
=137
10 years agoHelpfull: Yes(0) No(0)

The difference between two no is 9 and the product of the two is 14.What is the square of their sum?

a)120 b)130 c)137 d)145