between 1 and 100 total no of numbers divisible by 3 ,9 and 27

• Total number divisible by 3,9,27 are those which are divisible by 27.
  
  there are 3 such nos i.e. 27,54,81 between 1 and 100.
• 12 years agoHelpfull: Yes(6) No(2)
• @ Vignesh,
  
  Your statement is correct but according to that only 3 nos (27,54,81) are there which are divisible by all these three ( 3,9,27) numbers.
  
  Pls think again.
• 12 years agoHelpfull: Yes(2) No(2)
• Numbers divisible by 3 = 33numbers
  Numbers divisible by 9 = 11numbers
  Numbers divisible by 27= 3numbers
  
  Total no. of numbers = 33+11+3 = 47numbers overall.
• 12 years agoHelpfull: Yes(1) No(6)
• @ pargat,
  They ask total number of numbers which is divisible by all the three..
• 12 years agoHelpfull: Yes(1) No(5)
• and : 19 numbers
  by using this formula nth term = a + (n-1)d ,a = first term n = numb of terms d= diff
  number of terms diviible by 3 is 33
  number of terms diviible by 9 is 11
  number of terms diviible by 27 is 3
  every number divisible by 9 is divisible by 3 so 33 - 11 = 22 divisible by 3,9
  27 contain (27,54,81) which are already included in 3 table so 22-3= 19
  
• 11 years agoHelpfull: Yes(1) No(1)
• vignesh if you can not understand question properly then please don't answer.
  stupid.
• 11 years agoHelpfull: Yes(0) No(0)