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15x^2 -ax +60=0
if one root is square of other then find a
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- 15x^2 -ax +60=0
x^2 -(a/15)*x +4=0
If roots are p and p^2, then p^3=4; p = cube root(4)
a/15 = p+p^2 ; a= 15*(p+p^2) where p = cube root (4) - 12 years agoHelpfull: Yes(3) No(1)
- can some one give an answer clearly?
- 11 years agoHelpfull: Yes(1) No(1)
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