Two motor cycles A & B are started from one point at 4 Kmph & 6 Kmph; After 45 min B starts returning, at what time they will reach....

• Qn seems to be incomplete.
  
  No destination is given.
  
  If qn is
  
  at what time , they will meet, then
  
  
  Distance covered by A in 45 mins= 3 kms.
  Distance covered by B in 45 mins= 4.5 kms.
  
  Distance between and B after 45 mins= 1.5 kms.
  
  Relative speed when B is returning = 4+6=10 kmph
  Distance between A and B is covered in 1.5/10 = 0.15 hrs = 9 mins
  
  so they will meet again after 54 mins from starting time.
  
• 12 years agoHelpfull: Yes(16) No(2)
• B will reach back = 90minutes to the spot (1 and half hours)
  A will reach back = 135minutes to the spot(2 hours and 15 minutes)
  
  B reaching time :
  After 45min B starts returning means,
  B reach the certain place in 45min.
  Therefore,
  Distance covered by B in 45mins= 4.5kms.
  So, the place is about 4.5kms.
  
  So,B return back to the spot in same 45min
  Therefore, B reach the spot = 45min+45min = 90minutes(9kms)
  
  A reaching time:
  Time taken to reach 9km for A in 4kmph = 9/4 *60minutes =135minutes
  
  
  
  
  
• 12 years agoHelpfull: Yes(3) No(4)