In the reading room of a library, there are 10 tables, 4 chairs per table. In each table there are different numbers of people seated. How many ways they will sit in the library so that no chair would be blank?
a) 8 b)6 c)2 d)7

• mat b the question is wrong
  bcoz 'in each table there are different numbers of people seated. How many ways they will sit in the library so that no chair would be blank?'
• 14 years agoHelpfull: Yes(35) No(14)
• The question is wrong bcoz in total we have 40 chairs and their is no way we can fill all the chairs bcoz we have given a restriction that on each table different no of people are seated.so if on 1st table 4 chairs are occupied then on 2nd table we can occupy maximum of 3 chairs according to the given restriction.so we have left one chair.nw it will go on and we will be leaving chairs.so there is no way we can occupy all chairs.
• 13 years agoHelpfull: Yes(23) No(1)
• ans is 6. coz in first table 4 will be seated. in second table 3 will be seated. in third table 2 will be seated. in fourth table 1 person will be sit. so out of 10 4 r filled and 6 r left.
• 10 years agoHelpfull: Yes(3) No(5)
• There are 10 tables and 4 chairs per table.
  So there are a total of 10 x 4 = 40 chairs.
  we will assume the table to be a 4 seater table and in a four seater max of 8 people can sit in a close formation not more than that.
  Since the question only asks about the ways where the chairs should not be blank, then, the possible combinations are:
  1. 5 people per table covering 8 tables ( 40 chairs)
  2. 8 people per table covering 5 tables.
  3, 4 people per table covering 10 tables.
  4. 2 people per table covering 5 tables and 6 people per table covering 5 tables ( 10 + 30).
  5. 3 people per table covering 5 tables and 5 people covering 5 tables ( 15 + 25).
  6. 1 person covering 5 tables and 7 people covering 5 tables ( 5 + 35).
  
  so the maximum possible ways are 6.
  so the answer is b) 6
• 2 years agoHelpfull: Yes(0) No(0)