5,9,16,29,54,103,?

• 200
  
  5*2-1=9
  9*2-2=16
  16*2-3=29
  29*2-4=54
  54*2-5=103
  103*2-6=200
• 12 years agoHelpfull: Yes(33) No(1)
• Ans.200
  4,7,13,25,49,97
  3,6,12,24
• 12 years agoHelpfull: Yes(4) No(0)
• ans: 200
  solu:
  5+(5-1)=9
  9+(9-2)=16
  16+(16-3)=29
  29+(29-4)=54
  54+(54-5)=103
  103+(103-6)=200
• 12 years agoHelpfull: Yes(4) No(0)
• 5+4=9
  9+7=16
  16+13=29
  29+25=54
  54+49=103
  103+97=200
  
  the numbers added are 4,(4+3),(7+6),(13+12),(25+24),(49+48)
  
• 12 years agoHelpfull: Yes(2) No(1)
• series goes with *2-1,*2-2,*2-3,*2-4,*2-5
  so, the next term is 103*2-6=200
• 12 years agoHelpfull: Yes(0) No(2)
• for difference betweent next no and previous
  assum a=5,b=9
  b-a=ans:-9-5=4
  answer 4 and double the answer - 1= next no
  ie 4*2-1=7 add in the b , 9+7=16(next no)
  16(next no)-9(prev. no)=7
  7*2-1=13
  16+13=29
• 12 years agoHelpfull: Yes(0) No(1)
• missing number=200 ans.
  sol:-
  (9-5)*4+0=16
  (16-9)*4+1=29
  (29-16)*4+2=54
  (54-29)*4+3=103
  similarly,
  (103-54)*4+4=200 ans.
  
• 12 years agoHelpfull: Yes(0) No(1)
• ans: 200
  
  5 (+4) 9 (+2*4-1=7) 16 (+2*7-1=13) 29 (+2*13-1=25) 54 (+2*25-1=49) 103 (+2*49-1=97) 200
• 12 years agoHelpfull: Yes(0) No(0)
• 200
  
  5*2-1=9
  9*2-2=16
  16*2-3=29
  29*2-4=54
  54*2-5=103
  103*2-6=200
• 12 years agoHelpfull: Yes(0) No(0)
• 5+2*5/2-1=9
  9+2*4-1=16
  16+2*7-1=29
  29+2*13-1=54
  54+2*25-1=103
  103+2*49-1=200
• 12 years agoHelpfull: Yes(0) No(0)
• 200
  5*2-1=9
  9*2-2=16
  16*2-3=29
  29*2-4=54
  54*2-5=103
  103*2-6=200
• 5 years agoHelpfull: Yes(0) No(0)