Find sum of series: 1+ 0.1+0.001+0.0001+....

• 1.1011
  Less than 1.2
• 12 years agoHelpfull: Yes(9) No(10)
• 1+0.1+0.001/(1-1/10)=991/900
  after 1 and .1 the series go in g.p. and r=1/10 and a=.001
• 12 years agoHelpfull: Yes(8) No(0)
• there are 2 series. The sum of 1st series is 1/(1-10^(-3)) and sum of 2nd series is 10^(-1)/(1-10^(-3)) the sum of both is 1100/999=1.10110
• 12 years agoHelpfull: Yes(5) No(1)
• given series in gp
  hence sum of infinite tems is =a/(1-r)
  >1/(1-.1)=1/.9=10/9
• 10 years agoHelpfull: Yes(5) No(0)
• 1.11111111... Gp a/(1-r)
• 9 years agoHelpfull: Yes(0) No(0)