There is a temple, whose premises have a garden and a pond. It has 4
idols, each of Ram, Shiv, Vishnu and Durga. The priest plucks x flowers
from the garden and places them in the pond. The number of flowers
doubles up, and he picks y flowers out of them and goes to offer it to
Lord Ram. By the time he reaches to the pond, he finds the remaining
flowers also have doubled up in the meantime, so he again picks up y from
the pond and goes to Lord Shiv.This process is repeated till all the Gods
have y flowers offered to them, such that in the end no flower is left in
the pond. Find x and y.

• let initial flowers=x
  dey get double up that is nw we get 2x
  let y flowers be offered to GOD 1
  remaining are 2x-y which doubled that is 4x-2y
  again y flowers offered to GOD 2
  remainin are 4x-3y which doubled again that is 8x-6y
  again y flowers offered to GOD 3
  remainin are 8x-7y which doubled again that is 16x-14y
  again y flowers offered to GOD 4
  remainin are 16x-15y
  
  no flowers shud b left after
  therefore 16x-15y=0
  --> x/y=15/16
  
  so x=15 n y =16 atleast
  
  15*2=30,16 offer to god1
  14*2=28,16 offer to god2
  12*2=24,16 offer to god3
  8*2=16,16 offer to god4
  0 left
• 12 years agoHelpfull: Yes(126) No(8)
• x=15,y=16
  dip 15*2=30,16 offer to god1
  dip 14*2=28,16 offer to god2
  dip 12*2=24,16 offer to god3
  dip 8*2=16,16 offer to god4
  left 0..........
• 12 years agoHelpfull: Yes(16) No(10)
• ANS : (x,y) = (15n,16n) where n is any +ve integer.
  
  REASON :
  Flowers plucked from garden = x
  flowers offered to each God = y
  
  Initially it doubles to 2x
  when y flowers are offered to first God, 2x-y flowers remain.
  it doubles to 2(2x-y) = 4x-2y flowers.
  when y flowers are offered to second God, 4x-2y-y = 4x-3y flowers remain.
  it doubles to 2(4x-3y) = 8x-6y flowers.
  when y flowers are offered to third God, 8x-6y-y = 8x-7y flowers remain.
  it doubles to 2(8x-7y)= 16x-14y flowers.
  when y flowers are offered to Fourth God, 16x-14y-y = 16x-15y flowers remain.
  But we know that, after offering to the fourth God no flowers remain.
  Therefore 16x-15y = 0. or 16x = 15y or x/y = 15/16
  
  Also x/y = n*15/n*16 [dividing and multiplying by n]
  
  since x and y are to be counnting no.s or +ve integers,
  x = n*15 and y = n*16 where n is any +ve integer.
  for same value of n for both x and y.
  Therefore the possible values of x and y are 15,16 or 30,32 or 45,48 ...and so
  on.
• 12 years agoHelpfull: Yes(12) No(1)
• x=7 and y=8
  only flowers are offred to gods ram shiv vishnu
  first he pick 7 flowers form the garden and placed in pond now flowers=14
  14-8=6 remaining 6*2=12 offered 8 to ram
  12-8=4 remaining 4*2=8 offered 8 to shiv
  8-8=0 offered 8 to vishnu
  8-8=0
  
• 12 years agoHelpfull: Yes(6) No(28)
• x=15 and y=16
  initially 15*2=30
  30-16=14 , 16 to ram
  14*2=28 28-16=12 16 to shiv
  12*2=24 24-16=8 16 to vishnu
  8*2=16 16-16=0 16 to durga
• 12 years agoHelpfull: Yes(6) No(5)
• Let initially Xflowers
  after passing y to Ram 2*X-y in pond --> 4*X-2*y
  after passing y to Shiv 4*X-3*y in pond--->8*X-6*y
  after passing y to Vishnu 8X-7y in pond-->16X-14y
  after passing y to Durga 16X-15y in pond
  and given 16X-15y=0
  pick X=15
  Y=16
• 12 years agoHelpfull: Yes(4) No(4)
• x=15 y=16
  
  2(2(2(2x-y)-y)-y)-y=0
• 12 years agoHelpfull: Yes(3) No(3)
• simple yar...............taste with 999 botteles...and then u find 1 bottle...................it will consider poison
• 12 years agoHelpfull: Yes(1) No(19)
• priest rings x=15 flowers and offers y=16 flowers to all 4 gods. 2x=30 then -16 for 1st god = 14,again 2*14 =28-16(for 2nd god)=12, now 12*2=24-16(for 3rd god)=8, now 8*2 =16 -16(for forth god) .thus ends with zero.
• 11 years agoHelpfull: Yes(1) No(1)
• x=7,y=8
  8x-7y=0
• 11 years agoHelpfull: Yes(1) No(1)
• I=initial no of flowers in the pond
  P=no. of flowers picked up
  R=remaining flowers
  
  I P R
  2x y 2x-y
  2(2x-y) y 4x-3y
  2(4x-3y) y 8x-7y
  2(8x-7y) y 16x-15y
  
  accordingly,16x-15y should be zero.So 16x=15y,therefore the solution is x=15*k
  &y=16*k.where k=1,2,3,4,..............
• 11 years agoHelpfull: Yes(1) No(1)
• Another approach to solve it: start backwords:
  0 then y then y/2 then y/2+y then (y/2+y)/y and so on...
  
  final equation: (((y/2+y)/2+y)/2+y) = x
  
  solve it to get x/y = 15/16
  
  therefore: x = 15 and y = 16
  
  15*2=30,16 offer to god1
  14*2=28,16 offer to god2
  12*2=24,16 offer to god3
  8*2=16,16 offer to god4
  0 left
• 10 years agoHelpfull: Yes(1) No(0)
• final equation comes as 8x-14y = y,solving 8x=15y
  so x = 15,y=8
• 12 years agoHelpfull: Yes(0) No(10)
• x=8, y=16.
  
• 12 years agoHelpfull: Yes(0) No(1)
• initially no of flower was x
  then it became 2x
  after removing y flower it became 2x-y
  then it again become twice that is 2*(2x-y)
  again removing y flowers it became 2*(2x-y)-y
  again it become twice 2*[2*(2x-y)-y]
  removing y flower it become 2*[2*(2x-y)-y]-y
  again become twice 2*[ 2*[2*(2x-y)-y]-y]
  removing y flowers it become 2*[ 2*[2*(2x-y)-y]-y]-y
  now total no.of flowers became zero that is 2*[ 2*[2*(2x-y)-y]-y]-y=0
  solving we get ratio of x and y :: 15 and 16 respectively
  therefore x and y would be in ratio 15 and 16 respectively
  answer is x=15,y=16
  sorry for any fault
  
• 11 years agoHelpfull: Yes(0) No(1)
• x=32 y=30
  
• 11 years agoHelpfull: Yes(0) No(1)
• x=15n, y=16n , n=1,2,3,4,5.....
• 11 years agoHelpfull: Yes(0) No(0)
• X=31
  Y=32
  
• 10 years agoHelpfull: Yes(0) No(0)