The present ages of A,B and C are in proportions 4 : 7 : 9. Eight years ago, the sum of their ages was 56. What are their present ages (in years)?

Options
1) Insufficient data
2) 16, 30, 40
3) 16, 28 40
4) 16, 28, 36

• 4)16,28,36
  
  Let their ages 4x,7x,9x
  Ages 8yrs ago 4x-8,7x-8,9x-8
  So 4x-8+7x-8+9x-8 = 56
  => x=4
  then their present ages 4(4), 7(4), 9(4)
• 9 years agoHelpfull: Yes(0) No(0)