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Exam
Numerical Ability
Averages
There are eight bags of rice looking alike,seven of which have equal weight and one is slightly heavier.The weighing balance is of unlimited capacity.Using this balance ,the minimum number of weighing required to identify the heavier bag is
a) 2
b) 3
c) 4
d) 8
Read Solution (Total 4)
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- option a)2
two weighings are sufficient.
Place 3 bags on one pan and 3 bags on other pan.
If they are equal, one of the other two bags is heavier which can be found easily in second weighing.
If they are not equal, then put 1 bag from heavier lot in pan and 1 other bag from heavier lot in second pan.
If they are equal , third bag of heavier lot is heavier otherwise one heavier found in second weighing is heavier. - 12 years agoHelpfull: Yes(15) No(4)
- option a is correct
divide 8 bags into 3 groups 3,3,2
first compare 3,3
if it is equal, then the wrong bag is in next group
if it is not equal, then take the max weighted group - 12 years agoHelpfull: Yes(4) No(3)
- A minimum of three
- 8 years agoHelpfull: Yes(0) No(0)
- Ans 2 (a)
first we place 3 -3 on each side
whichever side get heavier we place 1-1 on next move - 6 years agoHelpfull: Yes(0) No(0)
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