m4maths
Maths Puzzle
Numerical Ability
Averages
32=2^5 1024=2^10
2^(10+10+5)
64=2^6 128=2^7
2^(6+13+7)
+2^(18+4+3)
Read Solution (Total 4)
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- Question is not clear.
- 12 years agoHelpfull: Yes(1) No(1)
- plz post question properly..
- 12 years agoHelpfull: Yes(0) No(1)
- TODAY'S PUZZLE:
32*(2^10)*1024 + 64*(2^13)*128 + 16*(2^18)*8 = ?
OPTIONS:
1) 3*(2^25)
2) 1*(2^26)
3) 1*(2^27)
4) 3*(2^26)
5) 1*(2^28)
6) 1*(2^25)
7) 3*(2^27)
8) (2^25)+3*(2^26)
9) 3*(2^25)+(2^26)
10) none of these - 12 years agoHelpfull: Yes(0) No(2)
- 32*(2^10)*1024 + 64*(2^13)*128 + 16*(2^18)*8=?
= 2^5*(2^10)*2^12 + 2^6*(2^13)*2^7 + 2^4*(2^18)*2^3
= 2^(5+10+12) + 2^(6+13+7) + 2^(4+18+3)
= 2^(25) + 2^(26) + 2^(25)
= 2^(25) +2^(25) +2^(25) +2^(25)
= 4*2^(25)
= 2^2 *2^(25)
= 2^(2+25)
= 2^(27)
Answer:2^(27) - 12 years agoHelpfull: Yes(0) No(2)
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