5 cards drawn at random one after another from a deck of 52 cards with replacement.The probablity that a spade card occurs at most once is .....

• no of spades = 13
  5 cards drawn one after another with replacement
  probability of no spade card is = 39/52 * 39/52 *39/52 *39/52 *39/52 = (3/4)^5
  probability of one spade is =( 1/4)(3/4)^4 + (1/4)(3/4)^4 + (1/4)(3/4)^4 + (1/4)(3/4)^4 + ( 1/4)(3/4)^4
  probabity of a spade cards at most once is = (3/4)^5 + ( 1/4)(3/4)^4 + (1/4)(3/4)^4 + (1/4)(3/4)^4 + (1/4)(3/4)^4 + ( 1/4)(3/4)^4 = 81/128
  hence answer is 81/128
• 9 years agoHelpfull: Yes(11) No(0)
• Probability of occurring 0 plus once
  5c0*(1-13/52)^5+5c1*(13/52)*(1-13/52)^4
  We get 81/128
• 9 years agoHelpfull: Yes(2) No(0)
• 1/1024
  no. of spades = 13
  0ut of 52 with replacemnet we can take 13 spades
  13 * 13* 13*13*!3
  total probability = 52 *52*52*52*52
  13*13*13*!3*13/52*52*52*52*52
  =1/1024
• 9 years agoHelpfull: Yes(1) No(10)
• please provide its answer
• 9 years agoHelpfull: Yes(0) No(0)
• since 5 cards r drawn 1 by 1 with replacement
  so no of possible 13*13*13*13*13
  probabability=13*13*13*13*13/52*52*52*52*52=1/1024
• 9 years agoHelpfull: Yes(0) No(1)
• ans=.63
  (39c4*13c1)/52c5 +(39c5*13c0)/52c5=.6328
  
  
• 9 years agoHelpfull: Yes(0) No(0)