The least number which when divided by 5, 6 , 7 and 8 leaves a remainder 3, but when divided by 9 leaves no remainder, is:

A. 1677 B. 1683
C. 2523 D. 3363

• B. 1683
  
  In simple words, a number which want to divisible by 9 without any remainder means,addition of the digits would be divisible by 9.
  
  So, by the given option,
  1677 = 1+6+7+7 ->21(not divisible by 9)
  1683 = 1+6+8+3 ->18(divisible by 9)
  2523 = 2+5+2+3 ->12(not divisible by 9)
  3363 = 3+3+6+3 ->15(not divisible by 9)
  
  So, answer would be B.1683
• 12 years agoHelpfull: Yes(7) No(5)
• (5*6*7*8)+3=1683
  
  now, 1683/9=187 with 0 remainder.. so answer is B.1683.
  
• 9 years agoHelpfull: Yes(0) No(0)