A merchant has 1000 kg of sugar, part of which he sells at 8% profit and the rest at 18% profit. He gains 14% on the whole. The quantity sold at 18% profit is:

A. 400 kg B. 560 kg
C. 600 kg D. 640 kg
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• ans is 600kg
  diff of profit from whole profit is 6% and 4% (14-8 && 18-4)
  Ration of 1st and 2nd parts = 4 : 6 = 2 : 3
  Quantity of 2nd kind =3x 1000kg = 600 kg.
  
  
• 12 years agoHelpfull: Yes(6) No(12)
• Let the parts be x & (1000-x) kgs sold at selling price of S1(@8% profit) & S2(@18% profit) respectively.
  Assuming that the cost price per kg of sugar is constant for both transactions, we have:
  (S1-x)/x =0.08
  [S2-(1000-x)]/(1000-x) =0.18
  Also, ts given that total profit is 14%. So,
  [(S1+S2)-1000]/1000 =0.14
  We need to find value of (1000-x) i.e the quantity sold @18% profit. Substitute S1,S2 in terms of x in the above eqn. We get: x=400. Thus, (1000-x)=1000-400=600 kgs
• 10 years agoHelpfull: Yes(2) No(0)