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Maths Puzzle
5.
A hollow iron pipe is 21 cm long and its external diameter is 8 cm. If the thickness of the pipe is 1 cm and iron weighs 8 g/cm3, then the weight of the pipe is:
A. 3.6 kg B. 3.696 kg
C. 36 kg D. 36.9 kg
Read Solution (Total 1)
-
- External radius = 4 cm
Internal radius = 3 cm [because thickness of pipe is 1 cm]
Volume of iron =πr2h=227∗[42−32]∗21cm3=227∗1∗21cm3=462cm3
Volume of iron =πr2h=227∗[42−32]∗21cm3=227∗1∗21cm3=462cm3
Weight of iron = 462*8 = 3696 gm
= 3.696 kg
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