In covering a distance of 30 km, Abhay takes 2 hours more than Sameer. If Abhay doubles his speed, then he would take 1 hour less than Sameer. Abhay's speed is:

A. 5 kmph B. 6 kmph
C. 6.25 kmph D. 7.5 kmph

• Let Time taken by Sameer=X hr ,D=30km ,S=D/T
  When Abhay speed is S then S=(30/(X+2))(coz abhay takes 2 hrs more than Sameer)--1
  When abhay speed is doubled i,e 2S then 2S=(30/(X-1))(coz abhay takes 1 hr less than Sameer)--2 Now divide eq1/eq2 then X=4Hrs
  Now substitute X in eq 2 we get S=5Kmph
  
  
  
• 10 years agoHelpfull: Yes(12) No(0)
• A.5 Kmph
  Abhay's Speed=5 Kmph & Sameer's Speed=7.5 Kmph
  According to condition Time taken for Abhay=30/5=6 Hrs. & for Sameer=30/7.5=4 Hrs.
  If Abhay doubles the speed,then time taken=30/10=3 Hrs.which is less than 1 Hr. by Sameer.
• 12 years agoHelpfull: Yes(7) No(7)
• Let Abhay's speed be x km/hr
  and sameer's speed be y km/hr
  
  Abhay takes 2 hours more than Sameer
  i.e (30/x)-(30/y)=2 ........ I
  
  Abhay doubles his speed, i.e his speed becomes 2x
  then he would take 1 hour less than Sameer
  
  i.e (30/y)-(30/2x)=1......... II
  
  ADD I and II
  you will get
  
  (30/x)-(30/2x)=3.......... III
  solve III you will get x=5 km/h
• 10 years agoHelpfull: Yes(7) No(0)
• let abhay' speed = x km/hr
  then, 30/x-30/2x=3
  6x=30
  x=5 km/hr
• 10 years agoHelpfull: Yes(1) No(5)
• suppose time taken by Sameer=x,
  then time taken by Abhay =x+2;
  according to question
  s=d/t
  s=30/x+2...........(1)
  2s=30/x-2..........(2)
  now divide eq1/eq2
  1/2=x-1/x+2
  x=4
  put the value of x in equ 1
  s=30/6
  s=5kmp/h
  
  
• 8 years agoHelpfull: Yes(1) No(1)
• let time taken by Sameer be x i.e. time taken by Abhay will be x+2
  
  since the distance travelled is 30km,
  
  Abhay's speed is 30/(x+2)
  
  if Abhay doubles his speed then he would take an hour less to complete the same distance than Sameer
  
  i.e.
  
  2(30/(x+2)) is the doubled speed of Abhay
  
  30/2(30/(x+2)) will be the time taken by him
  
  we know that time taken by Sameer is "x"
  
  but Sameer takes and hour longer than Abhay
  
  on equating this...
  
  (x+2)/2=x-1
  
  therefore on solving the above equation
  
  x=4 i.e.
  
  time taken by Abhay is 4+2=6 hours
  
  hence his speed will be = 30/6=5
  
  Abhay's speed is 5kmph
• 4 years agoHelpfull: Yes(0) No(0)