If ax = by, then:

A.
log a = x
b y
B.
log a = x
log b y
C.
log a = y
log b x
D. None of these

• the options are :
  Op 1: log(a/b) = x/y
  Op 2: log(a) / log(b) = x/y
  Op 3: log(a) / log(b) = y/x
  Op 4: None of these
  the question has to be a^x = b^y because if we take the option 3.(which is the answer) loga/logb=y/x
  back calculation gives us :
  x.loga=y.logb
  =>a^x = b^y hope it helps. :)
• 8 years agoHelpfull: Yes(2) No(1)
• log(ax) = log(by)
  loga+ log x= logb + log y
  ans d
• 9 years agoHelpfull: Yes(1) No(3)
• Op 1: log(a/b) = x/y
  Op 2: log(a) / log(b) = x/y
  Op 3: log(a) / log(b) = y/x
  Op 4: None of these
  Op 5:
  Correct Op : 3
• 10 years agoHelpfull: Yes(0) No(5)
• ax=by
  so now apply log both side
  log(a)x=log(b)y ........(1)
  now both log one side so eq is.
  log a/log b=y/x .....(2)
  so its proved ans is op. 3 only
  
• 9 years agoHelpfull: Yes(0) No(6)