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A polygon has 44 diagonals. Find the number of its sides
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- nC2 - n = 44 (given), then
½ n (n - 1) - n = 44
n^2 - n - 2 n = 88
n^2 - 3 n - 88 = 0
Solving the quadratic, we have
n^2 - 11 n + 8 n - 88 = 0
(n - 11) (n + 8) = 0
Since, n = -8 is not applicable, hence the polygon in question must have 11 number of sides to it - 5 years agoHelpfull: Yes(0) No(0)
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