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In how many ways a committee of 5 members can be selected from 6 men and 5 ladies consisting of 3 men and 2 ladies?
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- you have to select 3 men out of 6 men =6c3
and also 2 women out of 5 ladies= 5c2
Now
a committee of 5 members is == (6c3) * (5c2)
= 200 Answer - 7 years agoHelpfull: Yes(0) No(1)
- 6C3 * 5C2
total need 5 members
out off 11
6 men nd 5 women
i.e.,, 6C3 * 5C2 - 6 years agoHelpfull: Yes(0) No(0)
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