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Numerical Ability
Age Problem
. In a market 4 men are standing .The average age of the four before 2 years is 55, after some days one man is added and his age is 45. What is the average age of all?
a) 55 b)54.5 c)54.6 d)54.7
Read Solution (Total 6)
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- The average age of the four men before 2years = 55,
The sum of the ages of the four men before 2 years = 55*4=220,
Now, the sum of the ages of the four men at present = 220+(2+2+2+2)=228,
Then, the sum of the ages of 5 men = 228+45=273,
Therefore the average of all = 273/5 = 54.6 - 14 years agoHelpfull: Yes(49) No(1)
- av age of 4 persons now is 57.
Total age of 5 now is 57*4+45= 228+45= 273.
av age of 5= 273/5= 54.6 yrs - 14 years agoHelpfull: Yes(17) No(2)
- total age of 4 men is x
total age of 4 men before 2 year=x-8
avg age before 2 year=x-8/4=55
x-8=220
x=228
now,one men added of 45 year
so,avg age of 5 men =228+45/5=54.6year - 12 years agoHelpfull: Yes(7) No(1)
- avg age of 4 men b4 2 years is (x-(4*2))/4=55,
4*2 s used since it s 2 yrs back n 4 ppl r der
hence x=228
then when a man o age 45 s added avg will be (x+45)/5=y wkt x=228
(228+45)/5=54.6 - 14 years agoHelpfull: Yes(1) No(0)
- ans is 54.6
- 14 years agoHelpfull: Yes(0) No(4)
- 2 year back their ages average is 55*4=220
present age of all is 57*4=228
another member is added then 228+45=273/5=54.6 - 8 years agoHelpfull: Yes(0) No(0)
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