exam Maths Puzzle Numerical Ability

Factor completely: m^3-9m^2n+18n^2m
If anyone could help I would appricate it, I came up with m(m^2-9mn+18n^2) but it doesnt look right for some reason.

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Three times the larger of two numbers is equal to four times the smaller. The sum of the numbers is 21. Find the numbers the number N, in millions, of hearing imparied individual of age X can be approximated by N=-0.00006x^3+0.006x^2-0.1x+1.8. Approximate to the nearest million the number of hearing imparied individal of ages 25 and 50