Haretown and Tortoiseville are 99 miles apart. A hare travels at 10 miles per hour from Haretown to Tortoiseville, while a tortoise travels at 1 miles per hour from Tortoiseville to Haretown.

If both set out at the same time, how many miles will the hare have to travel before meeting the tortoise en route?

• 90 miles hare have to travel.
  
  Let t be the time before the hare and the tortoise meet.
  In t hours, the hare will travel 10t miles.
  In t hours, the tortoise will travel 1t miles.
  
  Now,
  10t + 1t = 99
  So, t = 99/11 = 9 hours.
  
  Thus, distance traveled by hare before meeting = 10* 9 = 90 miles.
  
  Where Distance = Speed *Time
• 12 years agoHelpfull: Yes(16) No(0)
• The relative speed is (10+1)miles per hour
  Both are going to meet =distance/relative speed
  =99/11=9hours
  After 9 hours they meet each other
  By that time the hare must have travelled =9*10=90 miles
• 12 years agoHelpfull: Yes(6) No(0)
• IF the both out at the same time then before they meet 1st travels will complete 90 miles and 2nd travels will complete 9 miles
• 12 years agoHelpfull: Yes(1) No(0)
• 80hrs
  hare=99m*10hr=9hrs 9mins
  tortoise=99*1hr=90hrs 9mins
  90hrs9mins-9hrs 9mins
• 12 years agoHelpfull: Yes(0) No(4)